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The char type can only represent a single character What's the difference between char* name which points to a constant string literal, and const char* name When you have a sequence of characters, they are piled next to each other in memory, and the location of the first character in that sequence is returned (assigned to test)
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Test is nothing more than a pointer to the memory location of the first character in testing, saying that the type it points to is a char. The fundamental difference is that in one char* you are assigning it to a pointer, which is a. As the initializer for an array of char, as in the declaration of char a [] , it specifies the initial values of the characters in that array (and, if necessary, its size)
} int main() { char *s = malloc(5)
// s points to an array of 5 chars modify(&s) // s now points to a new array of 10 chars free(s) } you can also use char ** to store an array of strings However, if you dynamically allocate everything, remember to keep track of how long the array of strings is so you can loop through each element and free it.
Is a pointer to the literal (const) string test The main difference between them is that the first is an array and the other one is a pointer The array owns its contents, which happen to be a copy of test, while the pointer simply refers to the contents of the string (which in this case is immutable). Technically, the char* is not an array, but a pointer to a char
Similarly, char** is a pointer to a char*
Making it a pointer to a pointer to a char Char *array = one good thing about music If you are printing a single character, you use the %c format specifier, and the matching argument should be a character (ie Where this array is allocated in memory, and how long it lives for, depends on where the declaration appears
If the declaration is within a function, it will live until the end of the block that it is declared in, and almost certainly be. 50 the difference between char* the pointer and char[] the array is how you interact with them after you create them If you are just printing the two examples, it will perform exactly the same They both generate data in memory, {h, e, l, l, o, /0}
