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It is worth mentioning that it is good practice to assign your pointer to null after the call to free, as this will prevent you from accidentally trying to access the freed memory (which is still possible, but absolutely should not be done). You can pass char * arguments to functions taking const char * arguments but opposite is not always true. 15 free releases the memory at that address
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It doesn't change the p variable itself You cannot free const char * because it is const However, doing anything with p after that point is undefined behavior
It may seem to work if you use it immediately after freeing, but it's still completely wrong, and could cause a crash or worse
This, plus of course many times p is only going to be a local stack variable anyway in which case having set it to null becomes irrelevant as soon as it goes out of scope Also, if there are multiple references to the same block of memory then they wouldn't all end up set to null if one of them was free'd, so it really wouldn't help much. The free function causes the space pointed to by ptr to be deallocated, that is, made available for further allocation If ptr is a null pointer, no action occurs.
The rest of your code isn't quite so safe: Allegedly, setting a pointer to null after free is supposed to prevent the dreaded double free problem when the same pointer value is passed to free more than once In reality though, in 9 cases out of 10 the real double free problem occurs when different pointer objects holding the same pointer value are used as arguments for free. (see also question 4.8.) a pointer value which has been freed is, strictly.
If the function failed to allocate the requested block of memory using malloc function, a null pointer is returned
So after allocation of memory, whether the p pointer is null or not If p is not a null pointer, we can the free the memory using free (p) Otherwise it causes undefined behavior. So most devs tested for null/0 before calling free.
