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Does anyone know a closed form expression for the taylor series of the function $f(x) = \\log(x)$ where $\\log(x)$ denotes the natural logarithm function? To gain full voting privileges, $$\ln \left (n^ {\ln\left (\ln (n)\right)}\right) = \ln \left ( \ln (n)^ {\ln (n)}\right)$$ recall that $\log_b a^c = c\log_b a$
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Use this property on both sides I thought it should be able to convert to ln x to the negative 1 then i can put it into the form 1/ ln x. $$\left (\ln\left (\ln (n)\right)\right)\left (\ln (n)\right)=\left (\ln (n)\right)\left (\ln\left (\ln (n)\right)\right)$$ this is true because multiplication is commutative.
How to solve if i have ln on both sides of equation
Ask question asked 11 years, 6 months ago modified 11 years, 6 months ago When we get the antiderivative of 1/x we put a absolute value for ln|x| to change the domain so the domains are equal to each other But my question is then why do we not do this for the derivative. This question is missing context or other details
Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level. Explanation for equivalence of ln 1/2 ask question asked 7 years, 11 months ago modified 7 years, 11 months ago We have seen the harmonic series is a divergent series whose terms approach $0$
