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I wrote the counting numbers joined together To gain full voting privileges, Which of the counting numbers was i writing when the 100th zero was written
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Answer by greenestamps (13209) (show source): Such a number is $ This is an infinite string of digits
But this string, when we try to interpret it in decimals, does not encode a number, i.e., an element of $ {\mathbb n}$ or $ {\mathbb r}$
Natural numbers, when written in decimals, appear as finite strings, and have a last digit Noninteger real numbers, when written in decimals, require a decimal point, after which an infinity of digits may appear. I found that the number $$123456789101112131415161718192021222324252627282931$$ which is prime number , i want to know if there is any simple method to show.
All positive integers are written in order, one after another $$1234567891011121314151617.$$ which digits appears in the 206 787th position? I have been curious about prime numbers lately and have been wondering what is the smallest prime number that is made of consecutive numbers as its digits Example of number for further clarificati. Find the remainder when the number $$1234567891011121314151617\\ldots200820092010$$ is divided by $9$
I don't even know where to begin
Is there an underlying trick in finding the This is a transcendental number, in fact one of the best known ones, it is $6+$ champernowne's number Kurt mahler was first to show that the number is transcendental, a proof can be found on his lectures on diophantine approximations, available through project euclid The argument (as typical in this area) consists in analyzing the rate at which rational numbers can approximate the constant.
How would you find the remainder when you divide $$1234567891011121314151617\\ldots201120122013$$ (the number formed by combining the numbers from $1$ to $2013$) by $75$? Bdmo 2013 rajshahi build a number by writing down consecutive natural numbers starting from $1$ which is divisible by $6$ and gives a reminder of $6$ upon division by $16$
